Building Pressurization Control for HVAC Engineers
Building Pressurization Control for HVAC Engineers
Building pressurization control maintains pressure differentials between spaces to control airflow direction, prevent infiltration/exfiltration, and ensure occupant comfort. Critical applications include laboratories, hospitals, cleanrooms, and stairwell pressurization.
Pressure Relationships
Pressure differential:
$$\Delta P = P_{high} - P_{low}$$
Typical units: Pascals (Pa) or inches water gauge ("w.g.)
Conversion: 1 "w.g. = 249 Pa
Airflow through opening:
$$Q = C \times A \times \sqrt{2 \Delta P / \rho}$$
Where:
- $Q$ = airflow (CFM)
- $C$ = discharge coefficient (0.6-0.7)
- $A$ = opening area (ft²)
- $\Delta P$ = pressure difference (lb/ft²)
- $\rho$ = air density (lb/ft³)
Simplified for standard air:
$$CFM = 2610 \times A \times \sqrt{\Delta P_{"w.g.}}$$
Worked Example 1: Leakage Through Door
Given:
- Door size: 3 ft × 7 ft
- Door gap: 0.5 inches all around
- Pressure differential: 0.05 "w.g.
- Discharge coefficient: 0.65
Find: Leakage airflow
Solution:
Gap area:
$$A = \frac{0.5}{12} \times 2 \times (3 + 7) = 0.833 \text{ ft}^2$$
Airflow:
$$CFM = 2610 \times 0.65 \times 0.833 \times \sqrt{0.05} = 390 \text{ CFM}$$
Answer: 390 CFM leakage through door gaps
Laboratory Pressurization
Negative Pressure Labs
Purpose: Contain hazardous materials (BSL-2, BSL-3, chemical labs)
Typical pressure: -0.01 to -0.05 "w.g. relative to corridor
Control strategy:
graph TD
A[Measure room pressure] --> B{Pressure < setpoint?}
B -->|Yes| C[Reduce exhaust airflow]
B -->|No| D[Increase exhaust airflow]
C --> E[Modulate exhaust valve/damper]
D --> E
E --> F{Fume hood active?}
F -->|Yes| G[Increase both supply + exhaust]
F -->|No| H[Maintain base ventilation]
Design:
- Exhaust > Supply by 100-300 CFM
- Exhaust located low (heavy vapors) and high (light vapors)
- Supply diffusers away from exhaust (avoid short-circuiting)
Positive Pressure Labs
Purpose: Protect sensitive materials (cleanrooms, semiconductor, pharmaceutical)
Typical pressure: +0.02 to +0.05 "w.g. relative to corridor
Design:
- Supply > Exhaust by 100-500 CFM (depends on room volume)
- Pressure cascades: Cleanroom > Gowning > Corridor
Cascade example:
- ISO 5 cleanroom: +0.05 "w.g.
- ISO 7 gowning: +0.03 "w.g.
- Corridor: +0.01 "w.g.
- Ambient: 0 "w.g.
Stairwell Pressurization
Purpose: Provide smoke-free egress during fires
Code requirements (IBC/NFPA 92):
- Minimum pressure: 0.10 "w.g. (25 Pa)
- Maximum pressure: 0.35 "w.g. (87 Pa) with all doors closed
Design airflow:
$$CFM_{stairwell} = CFM_{doors} + CFM_{leakage} + CFM_{weather}$$
Door opening airflow:
$$CFM_{door} = 2610 \times A_{door} \times \sqrt{\Delta P}$$
Typical: 3,000-5,000 CFM per stairwell
Worked Example 2: Stairwell Pressurization
Given:
- 10-story stairwell
- Door size: 3 ft × 7 ft = 21 ft²
- Design pressure: 0.30 "w.g. (single door open)
- Leakage: 200 CFM
Find: Required supply airflow
Solution:
Airflow for one door:
$$CFM_{door} = 2610 \times 21 \times \sqrt{0.30} = 30,000 \text{ CFM}$$
Total with leakage:
$$CFM_{total} = 30,000 + 200 = 30,200 \text{ CFM}$$
Answer: 30,200 CFM supply fan capacity
(Note: Actual design considers door-opening scenarios per NFPA 92)
Control strategy:
- Barometric damper relief (passive)
- Or modulating relief damper (active control)
- Pressure sensor in stairwell
Makeup Air for Exhaust Systems
Makeup air must replace exhausted air to prevent building depressurization
Calculation:
$$CFM_{makeup} = CFM_{exhaust} - CFM_{infiltration}$$
Sources of exhaust:
- Kitchen hoods: 200-500 CFM per linear foot
- Laboratory fume hoods: 100-150 CFM per ft² face area
- Restroom exhaust: 50-75 CFM per fixture
- Process exhaust: varies by application
Consequences of inadequate makeup air:
- Difficulty opening doors (high negative pressure)
- Backdrafting of combustion appliances
- Infiltration of unconditioned air
- Comfort complaints
Design guidelines:
- Provide 80-100% of exhaust as dedicated makeup air
- Remainder from infiltration and general ventilation
- Makeup air should be conditioned (heated/cooled)
Relief Air Sizing
Relief air prevents over-pressurization when outdoor air exceeds exhaust
Typical scenario: Economizer mode with 100% outdoor air
Sizing:
$$CFM_{relief} = CFM_{OA,max} - CFM_{exhaust} - CFM_{exfiltration}$$
Relief damper types:
- Barometric relief: Gravity-operated (passive)
- Power relief: Motorized damper (active control)
- Relief fan: Powered exhaust (large systems)
Location: High in building (warm air rises)
Practical Control Strategies
Direct Pressure Control
Sensor: Differential pressure sensor between spaces
Control: Modulates supply/exhaust dampers or fans to maintain setpoint
Advantages: Precise, responds to all influences (doors, wind, stack)
Disadvantages: Sensors drift, requires calibration
Airflow Tracking
Measure supply and exhaust flows, maintain offset
Example: Maintain supply = exhaust + 150 CFM
Advantages: No drift, simple to commission
Disadvantages: Does not account for infiltration/exfiltration
Combined Approach
Use airflow tracking with pressure monitoring as override/verification
Practical Design Considerations
- Sensor location: Away from diffusers, doors, HVAC equipment
- Door undercuts: 1-inch undercut = ~21 ft² × 1/12 = 1.75 ft² free area
- Vestibules: Break pressure differential (two-door airlock)
- Wind effects: Can overcome 0.05 "w.g. pressure control
- Commissioning: Test with doors open/closed, verify pressure cascades
Related Technical Guides:
References:
- ASHRAE Handbook of HVAC Applications, Chapter 16: Laboratories
- NFPA 92: Standard for Smoke Control Systems
- International Building Code (IBC), Section 909: Smoke Control Systems
- ANSI/AIHA Z9.5: Laboratory Ventilation